Azeotropes and Distillation Limits

Constant-boiling composition from vapour–liquid behaviour

Lesson 2039 of 4,500 · Solutions and Colligative Properties

Learning objectives

Introduction

Ordinary distillation separates volatile liquids because their vapour composition differs from their liquid composition. An azeotrope is a special composition at which the equilibrium vapour and liquid compositions coincide at a stated pressure. Repeated boiling and condensation cannot enrich a component past that composition by ordinary fractional distillation at the same pressure. The limitation follows from vapour–liquid equilibrium, not from inadequate patience or too few distillation cycles.

Core explanation

For a binary liquid, label the liquid mole fraction xA and equilibrium vapour mole fraction yA. Away from an azeotrope, yA often differs from xA, allowing a vapour fraction to become enriched in one component. At an azeotropic composition, yA = xA and yB = xB. The condensate has the same composition as the boiling liquid, so one ideal equilibrium step provides no composition improvement. An azeotrope behaves like a constant-boiling composition under fixed pressure, though it remains a mixture of chemical substances rather than becoming a new pure compound.

A positive deviation from Raoult's law can produce a pressure maximum at fixed temperature. A mixture with especially high vapour pressure can reach a chosen external boiling pressure at a lower temperature than neighbouring compositions. Under suitable conditions, that yields a minimum-boiling azeotrope. Ethanol–water is the familiar example at ordinary pressure. The mixture's exact azeotropic composition and boiling temperature depend on pressure and accurate equilibrium data; an introductory explanation does not need to claim the same numbers at every pressure.

A sufficiently strong negative deviation can produce a pressure minimum and, at a fixed external pressure, a maximum-boiling azeotrope. The pressure and boiling-temperature descriptions are complementary: at constant temperature, higher equilibrium pressure corresponds to easier vapour formation; at constant external pressure, that composition reaches boiling at a lower temperature. Do not compare a constant-temperature pressure plot directly with a boiling-temperature plot without noting which quantity is held fixed.

Not every nonideal solution forms an azeotrope. A curve may lie above or below the ideal line without reaching a pressure extremum or a point where yA = xA at the relevant conditions. Similarly, the pure endpoints have yA = xA trivially because only one component is present; calling pure A an azeotrope would misuse the term, which refers to a mixture at an interior composition.

In fractional distillation, many near-equilibrium steps enrich the more volatile component until the azeotrope is approached. At the azeotropic point, the equilibrium driving difference yA − xA is zero. Ordinary distillation at that pressure cannot pass it. Other separation methods can alter the phase equilibrium or use a different mechanism, such as changing pressure when the azeotropic composition moves, adding an appropriate third component under controlled design, or using a membrane process. The existence of such alternatives does not change the fixed-pressure distillation limit.

The phrase “constant boiling” needs care. At a given pressure, the azeotropic mixture boils at a constant temperature and its liquid and vapour compositions match during idealised equilibrium boiling. Impurities, changing external pressure, finite holdup and equipment losses can alter a real observation. Nor does a constant thermometer reading by itself prove an azeotrope; pure substances also boil at constant temperature under fixed pressure, and measurement conditions must be assessed.

Step-by-step reasoning

1. Identify the external pressure and compare liquid x with equilibrium vapour y. 2. If an interior mixture has xA = yA, identify an azeotropic composition. 3. Use a pressure maximum at fixed temperature as a clue toward minimum boiling; a pressure minimum as a clue toward maximum boiling. 4. Explain why y − x = 0 prevents further enrichment by ordinary same-pressure fractional distillation. 5. Avoid treating every positive or negative deviation as proof of an azeotrope.

Visual explanation

Draw a graph with liquid xA horizontally and vapour yA vertically. Include the diagonal yA = xA and a nonideal equilibrium curve crossing it at an interior point; label that crossing “azeotrope.” On a second sketch, show a pressure curve arched above the ideal line, with a maximum. Add “constant T” to the pressure graph and “fixed external P” beside its minimum-boiling interpretation.

Real-world analogy

Repeated steps up a staircase work only if each step raises you. Distillation steps enrich a component while vapour composition differs from liquid composition. At an azeotrope, the “step height” in composition is zero, so repeating the same kind of step at the same pressure gives no further enrichment. The analogy describes composition, not mechanical height or energy.

Real-world example

An ethanol–water mixture can approach a minimum-boiling azeotropic composition during ordinary fractional distillation at atmospheric pressure. The collected vapour becomes enriched in ethanol over much of the composition range, but near the azeotrope vapour and liquid compositions converge. Repeating the same pressure conditions cannot yield arbitrarily pure ethanol; a different separation approach is needed for a higher-purity target.

Why?

Why does equality yA = xA limit distillation? Condensing an equilibrium vapour of that composition gives a liquid with the same A fraction as the original boiling liquid. There is no composition gain for the next vaporisation–condensation stage.

Common misconception

“An azeotrope is a new chemical compound with a fixed formula.” It is a mixture whose phase equilibrium gives equal liquid and vapour compositions at a specified pressure. Its composition can shift when pressure changes, unlike a compound's stoichiometric formula.

Worked example

At a stated pressure, equilibrium data show that at liquid xA = 0.40 the vapour has yA = 0.62, while at liquid xA = 0.70 the vapour has yA = 0.70. Starting at xA = 0.40, condensing vapour would increase A fraction toward 0.62. At xA = 0.70, condensation gives the same 0.70, so this interior composition is an azeotropic candidate. These two pairs of values alone do not reveal whether its boiling temperature is a minimum or maximum; pressure or temperature versus composition data are also needed.

Quick check

1. What equality between liquid and vapour compositions defines a binary azeotrope at an interior mixture composition? Answer: xA = yA, which also implies xB = yB for a binary mixture.

Exam focus

Define the azeotrope by phase-composition equality, not merely constant temperature. Distinguish pressure maximum/minimum at fixed T from boiling minimum/maximum at fixed P. State the same-pressure ordinary distillation limit precisely.

Advanced insight

The azeotropic composition can depend on pressure because component activity coefficients and pure-component vapour pressures depend on temperature and pressure. This permits some pressure-swing separations when the shift is large enough, but feasibility requires full equilibrium data and process design. A classroom diagram alone cannot establish industrial separation performance.

Summary

At an azeotrope, equilibrium liquid and vapour have equal composition, preventing further enrichment by ordinary fractional distillation at the same pressure. Strong positive deviation may give a minimum-boiling azeotrope; strong negative deviation may give a maximum-boiling one. Deviation alone is not sufficient proof.

Practice questions

1. If a liquid has xA = 0.55 and its equilibrium vapour has yA = 0.55, what special behaviour is suggested? Answer: An interior azeotropic composition at the stated pressure, if the data are reliable. 2. Can ordinary fractional distillation at unchanged pressure enrich beyond such a point by repeating more stages? Answer: No. At the azeotrope, each equilibrium vapour has the same composition as its liquid. 3. Does a positive Raoult-law deviation always mean a minimum-boiling azeotrope exists? Answer: No. A suitable pressure maximum and equality of phase compositions must occur.