Selective Precipitation

Using differences in Ksp to separate ions from a mixture

Lesson 2606 of 4,500 · Inorganic Reasoning and Qualitative Analysis

Learning objectives

Introduction

Selective precipitation uses a reagent ion that forms solids of different solubilities with two dissolved ions. As the reagent ion concentration rises, one solid can reach Ksp first. That ordering may allow separation, but “first” is not enough: the first ion must be mostly removed before the second starts precipitating for a useful analytical separation.

Core explanation

For two monovalent cations M⁺ and N⁺ forming MX and NX, the onset of MX precipitation occurs when [M⁺][X⁻] = Ksp(MX). If M's free concentration before precipitation is cM, then [X⁻]onset,M = Ksp(MX)/cM. Likewise [X⁻]onset,N = Ksp(NX)/cN. Comparing these thresholds—not Ksp alone—determines which solid forms first. Different starting cation concentrations can reverse an ordering suggested by Ksp values.

Once MX solid is present, free [M⁺] at a controlled [X⁻] is approximately Ksp(MX)/[X⁻]. At the moment NX begins to precipitate, use its threshold [X⁻]onset,N in that expression. Dividing residual [M⁺] by its original cM gives the fraction remaining. This check quantifies whether there is a clean separation window.

For an illustrative hypothetical mixture, let cM = cN = 0.010 M, Ksp(MX) = 10⁻¹⁰ and Ksp(NX) = 10⁻⁶. M begins at [X⁻] = 10⁻⁸ M; N begins at 10⁻⁴ M. At the second onset, residual M⁺ is 10⁻¹⁰/10⁻⁴ = 10⁻⁶ M. Relative to 0.010 M initially, only 10⁻⁴ of M remains dissolved, meaning about 99.99% has precipitated under the ideal model. That is a much stronger separation claim than merely stating that M's Ksp is smaller.

Stoichiometry changes the threshold formula. For M(OH)₂, [OH⁻]onset = √(Ksp/[M²⁺]), not Ksp/[M²⁺]. For M₂X₃, both cation and anion powers follow the balanced formula. If one reagent anion is itself controlled by pH, as S²⁻ is in sulfide analysis, its free level cannot be equated to total reagent added. Acid-base equilibria and metal complexation may need to be solved first.

Selective precipitation is not automatically complete at equilibrium. Both ions can have small dissolved fractions, and coprecipitation may carry a second ion into the first solid by adsorption or solid-solution formation. Real separations also involve kinetics and filtration losses. The Ksp calculation predicts ideal free-ion distribution; observations and controls test how closely a practical separation approaches that ideal.

If the intended second ion is present at a very low concentration, its onset may require a much higher reagent ion level than expected, widening the window. Conversely, a high concentration can shrink the window. This is why analytical protocols specify concentration ranges and why a numerical problem must use actual starting amounts rather than a universal group ranking.

After precipitation, analyse solid and filtrate separately. The solid may be redissolved or transformed for a confirmation; the filtrate carries ions that did not precipitate appreciably. Reporting only the precipitate colour without tracking which phase contains each ion leaves the reasoning incomplete.

Step-by-step reasoning

1. Write each candidate solid's dissolution and Ksp expression. 2. Calculate onset reagent-ion level using each initial free cation concentration. 3. Order the thresholds to find a possible window. 4. At the second onset, calculate residual first-ion concentration. 5. Check complexation, pH effects and physical separation limits.

Visual explanation

Draw a horizontal axis of increasing free X⁻. Mark MX onset at a low value and NX onset at a higher value; show free M⁺ declining along the interval while N⁺ remains near its starting level.

Real-world analogy

Two gates open at different pressure settings. A useful separation requires enough time and pressure range for the first stream to leave before the second gate opens.

Real-world example

Carefully controlled reagent addition can separate metal ions by precipitating one salt while another remains dissolved. The remaining metal in the filtrate can then be tested separately.

Why?

Why can Ksp ordering alone be misleading? The onset depends on the ratio Ksp to the initial free metal concentration and on dissolution stoichiometry, not Ksp by itself.

Common misconception

“If one precipitate appears first, the separation is complete.” A substantial fraction of the first ion may still be dissolved when the second starts; calculate its residual level.

Worked example

In the hypothetical MX/NX mixture above, M starts precipitating at 10⁻⁸ M X⁻ and N at 10⁻⁴ M X⁻. At 10⁻⁴ M X⁻, free M⁺ is 10⁻⁶ M. Compared with its initial 10⁻² M, that is 0.01% remaining and 99.99% removed. The calculation assumes no complexes and unchanged volume; otherwise free-ion balances must be revised.

Quick check

1. Which quantity determines precipitation order for MX and NX when their initial concentrations differ? Answer: Their free X⁻ onset thresholds, Ksp(MX)/initial free [M⁺] and Ksp(NX)/initial free [N⁺], rather than Ksp values alone.

Exam focus

Compute both onset thresholds and residual first ion at the second threshold. State assumptions about free ions and no coprecipitation.

Advanced insight

OpenStax's selective precipitation examples appear at https://openstax.org/books/chemistry-2e/pages/15-1-precipitation-and-dissolution. Separation quality is a continuous fraction, so an analytical goal should specify acceptable residual contamination.

Summary

Different Ksp values can create a reagent-ion window in which one solid precipitates before another. Onset thresholds depend on starting free-ion concentrations and stoichiometry. Calculate residual first ion at the second onset to judge whether the window gives a useful separation.

Practice questions

1. What is [X⁻] onset for MX if Ksp = 10⁻⁹ and free [M⁺] = 10⁻² M? Answer: 10⁻⁷ M. 2. Why might changing pH alter metal-sulfide separation? Answer: It changes free S²⁻ through protonation equilibria. 3. What does a 1% residual first ion mean? Answer: About 99% was removed to the solid under the model. 4. Does an onset calculation alone include coprecipitation or adsorption? Answer: No. Those real effects require separate consideration or measurement.