Compound Formation and Incongruent Melting
Congruent compounds and peritectic behaviour
Lesson 3093 of 4,500 · Chemical and Statistical Thermodynamics I
Learning objectives
- Distinguish congruent from incongruent melting
- Identify a peritectic reaction on cooling
- Use phase compositions rather than overall formulas to interpret a diagram
Introduction
Binary phase diagrams can contain stable intermediate compounds as well as endpoint solids. A compound's written formula does not tell us whether it melts directly to a liquid of the same composition. Some melt congruently; others break down into a different solid and liquid at an invariant peritectic point. Reading phase fields and composition endpoints is more reliable than imagining that every stoichiometric solid simply liquefies at its formula composition.
Core explanation
An intermediate compound AB, or a compound with another fixed stoichiometry, can appear as a vertical composition line in a binary temperature–composition diagram if its solid homogeneity range is negligible. Congruent melting occurs when that solid is in equilibrium with a liquid of the same composition at its melting point. The liquidus can have a maximum at the compound composition. A sample of exactly that compound may then melt like a pure material at fixed pressure, although nearby compositions have broader phase behaviour.
Incongruent melting is different. On heating, an intermediate solid may transform into a liquid whose composition differs from the original solid plus another solid phase. On cooling, the reverse reaction is peritectic: liquid + primary solid → a new solid. One can write schematically L + α → β at a specified invariant temperature and compositions. This equation is a phase reaction; L, α and β denote phases with particular compositions, not necessarily pure species. Mass balance must hold across their amounts even though the liquid and both solids can have different compositions.
At fixed pressure in a binary system, three coexisting phases give F'=2−3+1=0. The peritectic temperature and the compositions of its equilibrium phases are fixed. The amounts are constrained by overall composition and history. If a cooling path first produces α from liquid, then reaches the peritectic isotherm, α can react with remaining liquid to form β. Under ideal slow equilibrium cooling, the reaction can proceed toward its balance-limited extent. Under rapid cooling, a shell of β may form around α and impede diffusion, leaving unreacted primary solid even though the equilibrium diagram predicts more conversion.
Distinguish a peritectic from a eutectic by the direction and participants on cooling. Eutectic: one liquid becomes two solids, L→α+β. Peritectic: liquid and one solid combine to give another solid, L+α→β. Both are invariant three-phase reactions at fixed pressure in a binary model. The difference matters for microstructure and whether existing solid must react, not just for memorising labels.
A vertical compound line is not automatically proof of congruent melting. Follow it upward and inspect which phase field or invariant line it meets. If it reaches a liquid of identical composition directly, melting is congruent. If it ends where another solid and a compositionally different liquid coexist, melting is incongruent. In complex diagrams, solid solutions, polymorphs or several intermediate compounds produce multiple peritectics; the simple cartoon is a local guide.
The equilibrium diagram assumes phases have reached equilibrium and ignores how long solid-state diffusion takes. Peritectic reactions can be slow because the product solid separates reactants. Practical solidification often yields segregation and metastable phases. Interpreting a cast alloy therefore requires both the equilibrium path and kinetic evidence.
Step-by-step reasoning
Locate the intermediate solid's composition and follow a fixed-composition heating path. At its first invariant boundary, list every coexisting phase and read endpoint compositions. If liquid has the solid's composition with no second solid, call melting congruent. If a different solid plus a different-composition liquid appear, call it incongruent; reverse the reaction for the cooling peritectic.
Visual explanation
Imagine a vertical line for compound β. In a congruent case it rises to a liquidus peak and meets liquid at the same horizontal composition. In an incongruent case it ends at a horizontal peritectic isotherm where liquid and another solid α are also present at different composition positions.
Real-world analogy
A prepared meal may dissolve directly into a uniform soup of the same ingredient ratio, or it may leave one ingredient behind while the liquid portion has a new ratio. This resembles congruent versus incongruent melting as a composition balance. The analogy is limited because solid–liquid equilibrium is governed by chemical potentials, not simple visual dissolution.
Real-world example
Ceramic and alloy processing often encounter intermediate phases that form through peritectic reactions. If a product layer surrounds an unreacted primary crystal, diffusion through the layer may be slow and the final microstructure may retain both. Phase diagrams predict equilibrium possibilities, while heat-treatment time determines how closely a real sample approaches them.
Why?
Why can a fixed-formula solid yield a different-composition liquid? At the invariant conditions, total Gibbs energy can be lower for a mixture of liquid and a second solid than for a single liquid of the compound's original composition. Overall atoms are conserved by choosing the right phase amounts; individual phase compositions need not match the starting solid.
Common misconception
“Incongruent melting violates mass conservation” is false. The products have different compositions, but their weighted sum equals the starting overall composition. Another error is to call L→α+β a peritectic; that is the standard eutectic direction on cooling, whereas a peritectic consumes an existing solid with liquid.
Worked example
Suppose solid β at overall B fraction 0.40 melts incongruently into solid α with x B=0.20 and liquid with x B=0.60 at the invariant temperature. The amount fractions satisfy 0.40=f α(0.20)+(1−f α)(0.60). Solving gives f α=0.50 and f L=0.50. Thus equal molar amounts of the two product phases conserve B, though neither has β's composition. Cooling the paired phases can reverse toward β under suitable equilibrium conditions.
Quick check
1. What is the schematic peritectic reaction on cooling, and how does it differ from a eutectic? Answer: A peritectic is L+α→β, consuming liquid and an existing solid. A eutectic is L→α+β, producing two solids from liquid.
Exam focus
Always state whether the diagram is being read on heating or cooling. Write phase compositions and a material balance when explaining incongruent melting. Use F'=0 to identify an invariant binary three-phase reaction at fixed pressure, but do not assume equilibrium kinetics are instantaneous.
Advanced insight
At a peritectic isotherm, chemical-potential equalities fix phase compositions, but phase fractions follow overall mass balance and the route by which phases were produced. In non-equilibrium solidification, product layers may trap primary solid and generate microsegregation. A full prediction may need diffusion modelling in addition to equilibrium thermodynamics.
Summary
Congruent melting gives liquid with the solid's composition. Incongruent melting yields another solid plus liquid of different composition; the reverse cooling event is peritectic, L+α→β. Eutectic and peritectic reactions both involve three phases at an invariant fixed-pressure binary point, but their phase sequences differ.
Practice questions
1. A compound melts to liquid of exactly its own composition without another solid. What type of melting is this? Answer: Congruent melting at the stated pressure and conditions. 2. On cooling, liquid and solid α combine to form β. Name the reaction. Answer: A peritectic reaction, L+α→β, at an invariant binary three-phase condition. 3. Does a formula line for AB guarantee congruent melting? Answer: No. Inspect the phase fields above the line; AB may instead decompose into a different solid and liquid. 4. Why might a peritectic transformation remain incomplete in a rapidly cooled sample? Answer: A β product layer can impede diffusion between remaining liquid and primary α, limiting reaction before cooling continues.