Iron-Sulfur Clusters
Cluster structures, electron transfer and protein stabilization
Lesson 3799 of 4,500 · Bioinorganic Chemistry
Learning objectives
- Describe the structures of [2Fe–2S], [3Fe–4S] and [4Fe–4S] clusters and their cysteine ligation
- Assign average iron oxidation states from cluster core charges
- Explain how the protein environment tunes cluster potential and protects clusters from damage
Introduction
Iron–sulfur clusters are among the most ancient cofactors in biology. They assemble from iron and sulfide and are held by cysteine side chains, forming small inorganic units embedded in proteins. They carry electrons in respiration, photosynthesis and nitrogen fixation, act as Lewis-acid catalysts, sense oxygen and iron, and even stabilise protein structure. Their versatility comes from delocalised electrons, variable nuclearity and exquisite tuning by the surrounding protein.
Core explanation
Rubredoxin as a starting point. The simplest iron–sulfur site has a single iron bound tetrahedrally by four cysteine thiolates, Fe(SCys)₄, with no inorganic sulfide. It cycles between Fe(III) and Fe(II). Strictly it is not a cluster, but it shows the tetrahedral thiolate environment common to all.
[2Fe–2S] clusters. Two iron atoms are bridged by two sulfide ions, forming a rhombus; each iron completes a tetrahedron with two terminal cysteines. In plant-type ferredoxins the couple is [2Fe–2S]²⁺/⁺, with potentials around −0.4 V. In Rieske centres one iron is bound by two histidines instead of cysteines, raising the potential to around +0.3 V and making the potential pH-dependent, because the histidines can be protonated.
[4Fe–4S] clusters. Four iron and four sulfide ions occupy alternate corners of a distorted cube (a cubane). Each iron is bound to one cysteine. Two couples are used:
- Ferredoxins: [4Fe–4S]²⁺/⁺, typically −0.3 to −0.5 V. - HiPIPs: [4Fe–4S]³⁺/²⁺, typically +0.1 to +0.4 V.
This is the "three-state" picture: the same cube can be in the 3+, 2+ or 1+ state, but a given protein uses only one pair.
[3Fe–4S] clusters are cubanes missing one iron corner. They often arise when a [4Fe–4S] cluster loses an iron, as in inactive aconitase.
Oxidation-state bookkeeping. In the [4Fe–4S]²⁺ core, four sulfides contribute 4 × (−2) = −8, so the four irons sum to +10: formally two Fe(III) and two Fe(II). Spectroscopy shows the extra electrons are delocalised, so pairs of irons behave as Fe^2.5+. With four cysteinate ligands (−1 each), the whole unit [Fe₄S₄(SCys)₄] carries a charge of 2−.
How the protein tunes potential. HiPIPs and ferredoxins contain the same cube yet differ by about 0.7 V in the couple used. The HiPIP cluster sits in a hydrophobic pocket with few N–H···S hydrogen bonds, so the more negatively charged 2+ and 1+ states are less stabilised and the 3+/2+ couple becomes accessible. Ferredoxin clusters are more exposed and have more hydrogen bonds, stabilising the reduced 1+ state. Solvent exposure, local dipoles and hydrogen bonding thus shift potentials by hundreds of millivolts.
Beyond electron transfer. In aconitase, one iron of a [4Fe–4S] cluster lacks a cysteine ligand and binds water; it acts as a Lewis acid, binding citrate and assisting its isomerisation to isocitrate. Radical SAM enzymes use a [4Fe–4S] cluster to cleave S-adenosylmethionine, producing a highly reactive radical. The bacterial regulator FNR senses O₂ when its [4Fe–4S] cluster converts to [2Fe–2S]. In some DNA repair enzymes a cluster helps hold the protein fold and may assist DNA binding.
Stability and assembly. Clusters are sensitive to O₂ and reactive oxygen species. Cells build them on scaffold proteins using sulfur released from cysteine by cysteine desulfurase, then transfer them to target proteins. The folded protein shields the cluster, and the cluster in turn stabilises the fold.
Step-by-step reasoning
1. Identify the cluster type from the numbers of iron and sulfide ions. 2. Add the charges of sulfides (−2 each) to the core charge to find total iron charge. 3. Divide by the number of irons to get the average oxidation state. 4. Identify the couple used and relate it to protein environment (exposure, hydrogen bonds, ligands).
Visual explanation
Draw a cube with iron and sulfur on alternating corners. From each iron, draw a line outwards to a cysteine sulfur attached to the protein backbone. Beside it, draw a rhombus of two irons and two sulfides, and a cube with one iron corner missing. Label each with its common redox couple and potential range.
Real-world analogy
The same model of battery cell can be wired into circuits at different voltages. A cube of iron and sulfide is similar: the protein decides which pair of charge states it can reach, just as a circuit design decides how a component is used. The analogy is limited because proteins shift the potential itself through electrostatics.
Real-world example
Friedreich's ataxia, an inherited neurological disease, results from low levels of frataxin, a protein involved in iron–sulfur cluster assembly in mitochondria. Deficient cluster assembly impairs respiratory complexes and aconitase, and iron accumulates in mitochondria, illustrating how essential these small inorganic units are.
Why?
Why is electron delocalisation useful? Spreading an added electron over several iron atoms reduces the structural change on reduction. Bond lengths change little, so the reorganisation energy is low and electron transfer is fast. Delocalisation also buffers the cluster against localised charge build-up.
Common misconception
"All [4Fe–4S] clusters have similar potentials." The same core supports couples separated by nearly a volt. Both the choice of couple (3+/2+ or 2+/1+) and the protein environment determine the potential.
Worked example
Question: Find the average iron oxidation state in the [4Fe–4S]³⁺ core of an oxidised HiPIP and in the [2Fe–2S]⁺ core of a reduced ferredoxin.
Reasoning: For [4Fe–4S]³⁺: iron total = +3 + 8 = +11, average = 11/4 = +2.75. For [2Fe–2S]⁺: iron total = +1 + 4 = +5, average = +2.5.
Answer: +2.75 (three Fe(III) and one Fe(II) formally) and +2.5 (one Fe(III) and one Fe(II) formally).
Quick check
1. What structural feature of a Rieske centre raises its potential above that of a plant ferredoxin? Answer: One iron is coordinated by two histidines instead of two cysteines, which stabilises the reduced state and raises the potential.
Exam focus
Draw and name [2Fe–2S], [3Fe–4S] and [4Fe–4S] clusters with their cysteine ligands. Calculate average iron oxidation states from core charges. Explain the HiPIP versus ferredoxin difference in terms of protein environment, and give at least one non-electron-transfer role.
Advanced insight
Nitrogenase contains the most complex biological iron–sulfur cluster, the iron–molybdenum cofactor, MoFe₇S₉C, with a central carbide ion. Its electronic structure and the way it binds N₂ remain active research topics. Mössbauer and EPR spectroscopy are essential tools: Mössbauer resolves iron sites and their valence, while EPR detects half-integer spin states such as the S = 1/2 state of reduced [4Fe–4S]⁺ clusters.
Summary
Iron–sulfur clusters contain iron bridged by sulfide and bound by cysteine. [2Fe–2S], [3Fe–4S] and [4Fe–4S] clusters transfer single electrons with low reorganisation energy thanks to delocalised mixed valence. The protein selects the couple and tunes potential through exposure, hydrogen bonding and ligand choice. Clusters also catalyse reactions, sense signals and stabilise protein structure, and require dedicated assembly machinery.
Practice questions
1. What is the charge of the unit [Fe₄S₄(SCys)₄] when the core is [4Fe–4S]²⁺? Answer: 2+ from the core plus four cysteinates at −1 each gives an overall charge of 2−. 2. Why do HiPIPs use the 3+/2+ couple while ferredoxins use 2+/1+? Answer: HiPIP clusters are buried in a hydrophobic pocket with few hydrogen bonds, destabilising more reduced states, whereas ferredoxin clusters are more exposed and hydrogen-bonded, stabilising the 1+ state. 3. Describe the non-redox role of the cluster in aconitase. Answer: A unique iron lacking a cysteine ligand acts as a Lewis acid, binding citrate and assisting its conversion to isocitrate via dehydration and rehydration. 4. Why is the reorganisation energy of iron–sulfur clusters small? Answer: The added electron is delocalised over several irons, so bond lengths change little between redox states.