Key relationship
v=√(GM/r); T=2π√(r³/GM); E=−GMm/(2r).
Physics · Class 11
Gravity supplies centripetal acceleration in a circular orbit. Higher orbits have lower speed but greater circumference, so the period grows. Their total orbital energy is less negative.
Open the interactive experiment →வட்டச் சுற்றுப்பாதையில் ஈர்ப்பு விசை மையநோக்கு விசையாகும். உயரம் அதிகரித்தால் வேகம் குறைந்து சுற்றுக்காலம் அதிகரிக்கும்.
v=√(GM/r); T=2π√(r³/GM); E=−GMm/(2r).
Gravity supplies centripetal acceleration in a circular orbit. Higher orbits have lower speed but greater circumference, so the period grows. Their total orbital energy is less negative.
Satellite weight is not zero in orbit; gravity continuously bends the trajectory.
Circular exterior orbit about spherical Earth; no atmosphere, thrust or perturbations. Altitude is added to Earth radius.
Relate orbital radius, speed, period and total energy.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
At 400 km altitude, r=6.771×10⁶ m, v≈7.673 km/s and T≈5545 s, about 92.4 minutes.
The model connects resize a satellite orbit with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
If orbital radius doubles, how does period change?
T is proportional to r^(3/2), so T(2r)/T(r)=2^(3/2).
Course connection: Class XI Chapter 7. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.