Key relationship
qA′ = qA − f(qA−qB)/2; qB′ = qB + f(qA−qB)/2.
Physics · Class 12
Two identical conducting spheres share charge when joined. Move the equalisation fraction from separated to fully connected and check the conserved total.
Open the interactive experiment →ஒத்த கடத்திக் கோள்களை இணைத்தால் மின்னூட்டம் பகிர்கிறது. மொத்த மின்னூட்டம் மாறாது.
qA′ = qA − f(qA−qB)/2; qB′ = qB + f(qA−qB)/2.
Two identical conducting spheres share charge when joined. Move the equalisation fraction from separated to fully connected and check the conserved total.
Charge is transferred, not created. The total charge of the isolated two-conductor system stays fixed.
Identical isolated conducting spheres, far apart after contact; no charge leakage. Fraction models progress to equal sharing, not a transfer rate.
Use the controls and plotted relation to explain charge transfer and conservation.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
For +8 and −2 µC, full contact gives (8−2)/2 = +3 µC on each sphere.
The model connects charge transfer and conservation with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
Initially A has +8 µC and B has −2 µC. After equal sharing?
Each sphere has +3 µC; the total remains +6 µC.
Course connection: Class XII Chapter 1. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.