Key relationship
I=ε/(R+r); Vterminal=ε−Ir.
Physics · Class 12
EMF is energy supplied per unit charge inside the source. Internal resistance causes terminal voltage to drop when a load draws current.
Open the interactive experiment →மூலத்தின் உள்ள்மின்தடையில் Ir மின்னழுத்த இழப்பு உண்டு. மின்னோட்டம் செல்லும்போது முனை மின்னழுத்தம் EMF-ஐவிடக் குறையும்.
I=ε/(R+r); Vterminal=ε−Ir.
EMF is energy supplied per unit charge inside the source. Internal resistance causes terminal voltage to drop when a load draws current.
A discharging cell’s terminal voltage is below its EMF by Ir. Open-circuit EMF and loaded terminal voltage are different readings.
The cell EMF and internal resistance stay fixed while it supplies a positive resistive load. This does not model battery chemistry, charging or changing charge capacity.
Use the controls and plotted relation to explain emf and terminal voltage.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
With ε=1.5 V, r=0.5 Ω and R=5 Ω, I≈0.273 A and V≈1.364 V.
The model connects emf and terminal voltage with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
When a cell delivers current, its terminal voltage is?
EMF minus the internal drop Ir.
Course connection: Class XII Chapter 3. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.