Key relationship
I₁=I₂+I₃; ε−I₁R₁−I₂R₂=0; I₂R₂=I₃R₃.
Physics · Class 12
One series resistor feeds two parallel branches. Changing one branch changes the node voltage and both branch currents. The readout verifies charge conservation at the junction.
Open the interactive experiment →சந்தியில் வரும் மின்னோட்டம் வெளியேறும் மின்னோட்டங்களின் கூட்டுத்தொகை. மூடிய சுற்றில் மின்னழுத்தங்களின் கூட்டுத்தொகை பூஜ்யம்.
I₁=I₂+I₃; ε−I₁R₁−I₂R₂=0; I₂R₂=I₃R₃.
One series resistor feeds two parallel branches. Changing one branch changes the node voltage and both branch currents. The readout verifies charge conservation at the junction.
Choose current and loop directions consistently. A negative answer means the actual current is opposite to the assumed direction.
An ideal DC source feeds one series resistor and two parallel branches with fixed resistances. The panel checks this circuit topology rather than solving an arbitrary circuit.
Use the controls and plotted relation to explain kirchhoff junction and loop rules.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
For ε=12 V, R₁=10 Ω, R₂=20 Ω, R₃=30 Ω, I₁=0.545 A, I₂=0.327 A and I₃=0.218 A.
The model connects kirchhoff junction and loop rules with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
Kirchhoff junction law follows from conservation of?
Electric charge.
Course connection: Class XII Chapter 3. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.