Key relationship
F⃗=q(E⃗+v⃗×B⃗); r=mv⊥/(|q|B).
Physics · Class 12
Only velocity perpendicular to B contributes to magnetic force. Parallel velocity gives no magnetic force. The magnetic-only circular radius is shown separately from the chosen electric force.
Open the interactive experiment →காந்தவிசை qvB sinθ. வேகம் காந்தப்புலத்திற்கு இணையாக இருந்தால் விசை பூஜ்யம்.
F⃗=q(E⃗+v⃗×B⃗); r=mv⊥/(|q|B).
Only velocity perpendicular to B contributes to magnetic force. Parallel velocity gives no magnetic force. The magnetic-only circular radius is shown separately from the chosen electric force.
A magnetic force is perpendicular to velocity and does no work. The parallel velocity component does not set the gyration radius.
Nonrelativistic particle. Electric force is chosen along the measured magnetic-force component. Radius applies to magnetic-only motion; zero B/q returns zero as a no-circle indicator.
Use the controls and plotted relation to explain lorentz force and circular motion.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
At q=1 nC, v=10 km/s and B=10 mT perpendicular to v, magnetic force is 10⁻⁷ N.
The model connects lorentz force and circular motion with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
A particle moving parallel to uniform B experiences magnetic force?
Zero.
Course connection: Class XII Chapter 4. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.