Key relationship
F=−cv; c=geometry·B²/R; v=v₀ exp(−ct/m).
Physics · Class 12
A moving conductor develops eddy currents that resist motion. This effective-loop model shows increased braking with stronger field and smaller loop resistance.
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F=−cv; c=geometry·B²/R; v=v₀ exp(−ct/m).
A moving conductor develops eddy currents that resist motion. This effective-loop model shows increased braking with stronger field and smaller loop resistance.
Magnetic braking converts kinetic energy into heat in induced currents; the damping coefficient here is a geometry-dependent approximation.
Lumped effective eddy loops, linear magnetic drag and constant B; excludes skin effect and detailed plate geometry.
Use the controls and plotted relation to explain eddy-current magnetic braking.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
With geometry=2 m², B=0.5 T and R=1 Ω, c=0.5 kg/s; a 1 kg plate retains e⁻¹ of its speed after 2 s.
The model connects eddy-current magnetic braking with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
Stronger B in this eddy-current braking model gives?
More braking because damping is proportional to B².
Course connection: Class XII Chapter 6. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.