Key relationship
λ=c/f; Ephoton=hf.
Physics · Class 12
Move continuously from radio to gamma rays. Frequency increases as wavelength decreases; photon energy rises with frequency. Spectrum boundaries are conventional and overlap between sources and uses.
Open the interactive experiment →ரேடியோ முதல் காமா வரை அதிர்வெண் உயரும்போது அலைநீளம் குறையும். ஒளித்துகள் ஆற்றல் hf ஆகும்.
λ=c/f; Ephoton=hf.
Move continuously from radio to gamma rays. Frequency increases as wavelength decreases; photon energy rises with frequency. Spectrum boundaries are conventional and overlap between sources and uses.
Increasing frequency shortens vacuum wavelength and increases photon energy. Spectrum boundaries are conventional approximate ranges.
Vacuum wavelength; approximate conventional band boundaries. Typical uses: radio communication, microwave links/heating, infrared thermal sensing, visible vision, UV fluorescence, X-ray imaging, gamma nuclear spectroscopy.
Use the controls and plotted relation to explain electromagnetic spectrum.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
At f=10¹⁴ Hz, λ≈3 µm and photon energy≈0.414 eV (infrared).
The model connects electromagnetic spectrum with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
Higher frequency electromagnetic radiation has?
Shorter wavelength and greater photon energy.
Course connection: Class XII Chapter 8. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.