Key relationship
Each active quadratic degree contributes ½kBT per molecule; U=f nRT/2.
Physics · Class 11
Equipartition assigns equal average energy to each active quadratic degree of freedom. Adding active rotational or vibrational terms raises total energy and heat capacity at the same temperature. A vibrational mode contributes two quadratic terms.
Open the interactive experiment →செயல்படும் ஒவ்வொரு இருபடிச் சுதந்திரக் கூறுக்கும் சராசரியாக ½kBT ஆற்றல் கிடைக்கும். கூறுகள் அதிகரித்தால் உள் ஆற்றல் அதிகரிக்கும்.
Each active quadratic degree contributes ½kBT per molecule; U=f nRT/2.
Equipartition assigns equal average energy to each active quadratic degree of freedom. Adding active rotational or vibrational terms raises total energy and heat capacity at the same temperature. A vibrational mode contributes two quadratic terms.
A vibrational oscillator supplies kinetic and potential quadratic terms.
Classical equipartition only for thermally active quadratic modes. Quantum freezing at low temperatures and vibrational activation are represented by choosing f, not by an automatic temperature-dependent mode calculation.
Count active quadratic terms and apply equipartition.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
At f=5, n=1 mol and T=300 K, each quadratic mode has RT/2≈1247.17 J and the total is 6235.85 J.
The model connects distribute energy across active modes with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
For five active degrees of freedom, what is molar Cv?
U=5nRT/2, so differentiating with respect to T gives Cv=5R/2 per mole.
Course connection: Class XI Chapter 12. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.