Key relationship
x′ = x − vbus t; v′ = v − vbus
Physics · Class 11
Position and velocity need an observer. The roadside origin stays at x = 0. The bus origin moves at the bus velocity, so its coordinates subtract the bus displacement. Both descriptions refer to the same walker at the same time.
Open the interactive experiment →நிலை மற்றும் திசைவேகம் பார்வையாளரைச் சாரும். பேருந்தின் இடப்பெயர்ச்சியை சாலை நிலையில் இருந்து கழித்தால் பேருந்து சார்ந்த நிலை கிடைக்கும்.
x′ = x − vbus t; v′ = v − vbus
Position and velocity need an observer. The roadside origin stays at x = 0. The bus origin moves at the bus velocity, so its coordinates subtract the bus displacement. Both descriptions refer to the same walker at the same time.
A negative velocity in the bus frame does not imply a negative velocity on the road.
One dimension; constant bus and walker velocities; origins coincide at t = 0; clocks agree. The bus frame is inertial.
Transform positions and velocities between the roadside and a uniformly moving bus.
Play the journey, switch observers, then try equal bus and walker velocities. Compare both coordinate lines.
A person beside your moving bus can seem to move backward even while walking forward along the road.
With x0 = 10 m at t = 5 s, the walker is at 20 m on the road. The bus origin is at 30 m, so the walker is at x′ = −10 m.
An explicit observer prevents contradictory descriptions of a single event.
Signed numbers · coordinates · gradients · area under a graph
A walker moves at +2 m/s and the bus at +6 m/s on the road. What is the walker velocity seen from the bus?
Subtract the observer velocity: v′ = 2 − 6 = −4 m/s. The walker falls behind the bus.
Course connection: CBSE XI Chapter 2; NEET and JEE Main Unit 2; JEE Advanced Mechanics. Check the selected syllabus for relative-velocity scope.