Key relationship
Isothermal pV=constant, W=nRTln(V₂/V₁). Reversible adiabatic pV^γ=constant, TV^(γ−1)=constant.
Physics · Class 11
An isothermal gas exchanges heat to keep its temperature fixed as it expands. A reversibly adiabatic gas receives no heat, so expansion work lowers its internal energy and temperature. The adiabatic pressure falls more steeply.
Open the interactive experiment →சமவெப்ப நிகழ்வில் வெப்பநிலை மாறாது. வெப்பமாற்றமற்ற விரிவில் வாயு வேலை செய்வதால் வெப்பநிலை குறையும்.
Isothermal pV=constant, W=nRTln(V₂/V₁). Reversible adiabatic pV^γ=constant, TV^(γ−1)=constant.
An isothermal gas exchanges heat to keep its temperature fixed as it expands. A reversibly adiabatic gas receives no heat, so expansion work lowers its internal energy and temperature. The adiabatic pressure falls more steeply.
Adiabatic does not mean constant temperature.
Quasistatic ideal-gas processes with constant heat capacities. Adiabatic path is reversible; compression has Wby<0. Isothermal heat equals work because ΔU=0.
Compare thermodynamic paths, heat exchange, temperature and work.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
For 1 mol at 300 K expanded to twice the volume, isothermal W=RTln2≈1728.9 J. With γ=1.4, adiabatic T₂=300×2⁻⁰·⁴≈227.36 K.
The model connects compare isothermal and adiabatic paths with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
In reversible adiabatic expansion of an ideal gas, what happens to temperature?
Q=0 and Wby>0 give ΔU=−Wby<0; ideal-gas internal energy follows temperature.
Course connection: Class XI Chapter 11. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.