Key relationship
p=F₁/A₁=F₂/A₂; A₁x₁=A₂x₂.
Physics · Class 11
Mechanical Properties of Fluids
A pressure increase applied to a confined fluid reaches both pistons. The larger piston produces more force, but moves a smaller distance so the ideal lift conserves work.
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p=F₁/A₁=F₂/A₂; A₁x₁=A₂x₂.
A pressure increase applied to a confined fluid reaches both pistons. The larger piston produces more force, but moves a smaller distance so the ideal lift conserves work.
A hydraulic force gain is not an energy gain.
Connected incompressible fluid, pistons at equal height, no friction or losses. The output force gain trades off against output distance.
Predict force and displacement trade-offs in a hydraulic machine.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
A 10 cm input stroke moves the output 0.5 cm. Input work=100×0.1=10 J, equal to 2000×0.005=10 J.
The model connects link a pair of pistons with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
For piston areas 5 and 100 cm², what output comes from 100 N?
The area ratio is 100/5=20, so F₂=20×100 N.
Course connection: Class XI Chapter 9. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.