Key relationship
L₁+e=λ/4; L₂+e=3λ/4; c=2f(L₂−L₁).
Physics · Practical apparatus
Slide the water level to change the closed air column. Locate two resonance peaks; their separation removes the common open-end correction. Peak width is an illustrative apparatus response parameter.
Open the interactive experiment →மூடிய காற்றுக்குழாயின் அடுத்தடுத்த ஒத்ததிர்வு நீளங்களின் வேறுபாடு λ/2. இரு நீளங்களால் முனைத் திருத்தம் ரத்தாகும்.
L₁+e=λ/4; L₂+e=3λ/4; c=2f(L₂−L₁).
Slide the water level to change the closed air column. Locate two resonance peaks; their separation removes the common open-end correction. Peak width is an illustrative apparatus response parameter.
Use the difference between successive resonant lengths; their common end correction then cancels.
closed-open tube, end correction 0.6 radius; response is a pair of Lorentzian peak indicators, not measured sound amplitude. Higher resonances omitted.
Adjust resonance-tube sound speed apparatus, observe its reading and derive the indicated physical quantity.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
c=2×512×0.335≈343.04 m/s.
The model connects resonance-tube sound speed with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
For f=512 Hz and resonance separation 0.335 m, sound speed is?
Approximately 343 m/s.
Course connection: Virtual apparatus preparation. Check exact board/exam membership in the syllabus sources. Physical practical work remains necessary.