Key relationship
F=Gm₁m₂/r²; gA=Gm₁/r².
Physics · Class 11
Every pair of masses attracts. The inverse-square relationship means doubling separation reduces the force to one quarter. Changing either mass scales the force linearly.
Open the interactive experiment →ஈர்ப்பு விசை நிறைகளின் பெருக்கலுக்கு நேர்விகிதத்திலும் இடைத்தொலைவின் வர்க்கத்திற்கு எதிர்விகிதத்திலும் இருக்கும்.
F=Gm₁m₂/r²; gA=Gm₁/r².
Every pair of masses attracts. The inverse-square relationship means doubling separation reduces the force to one quarter. Changing either mass scales the force linearly.
The distance in the law is between centres for spherical masses.
Separated spherical bodies treated as point masses; centre-to-centre distance is much larger than their radii. Newtonian gravity.
Explore inverse-square attraction and distinguish force from field.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
For 10⁷ kg and 2×10⁷ kg at 100 m, F=6.6743×10⁻¹¹×2×10¹⁴/10⁴=1.33486 N.
The model connects separate two attracting masses with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
If separation doubles with fixed masses, what happens to force?
F is proportional to 1/r², hence F(2r)=F(r)/4.
Course connection: Class XI Chapter 7. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.