Key relationship
Indicated reading = main scale + coinciding division × least count. Corrected reading = indicated reading − zero error.
Physics · Practical apparatus
A vernier compares two scales with slightly different divisions. Ten vernier divisions span nine millimetres, so adjacent divisions differ by 0.1 mm. The coinciding line identifies the fractional part of a millimetre. A positive zero error makes the indicated value too large; subtract it.
Open the interactive experiment →வெர்னியர் அளவுகோலில் பொருந்தும் கோட்டின் எண்ணை மீச்சிற்றளவால் பெருக்கி முதன்மை அளவுடன் சேர்க்க வேண்டும். பூஜ்யப் பிழையை அளவீட்டிலிருந்து கழிக்க வேண்டும்.
Indicated reading = main scale + coinciding division × least count. Corrected reading = indicated reading − zero error.
A vernier compares two scales with slightly different divisions. Ten vernier divisions span nine millimetres, so adjacent divisions differ by 0.1 mm. The coinciding line identifies the fractional part of a millimetre. A positive zero error makes the indicated value too large; subtract it.
A positive zero error is subtracted, not added.
Ideal outer-jaw, inner-jaw and depth-rod measurement with 1 mm main divisions. The jaw/rod travel is rounded to the nearest vernier division. The expanded scale shows the actual coincidence. Known zero error is subtracted; the remaining rounding bound is ± half the least count. Correct alignment and contact are assumed; jaw wear, force and parallax are outside this model.
Read main and vernier scales; calculate least count; correct signed zero error.
Change the jaw opening. Identify the highlighted coinciding line, then introduce a known zero error and compare the corrected value.
Two slightly different combs reveal a fine shift by which pair of teeth lines up.
For 10 vernier divisions: least count = 1 − 9/10 = 0.1 mm. Main scale 23 mm plus coincidence 4 gives 23.4 mm.
Fine resolution and zero correction solve different problems; a finer scale cannot remove a calibration error.
Decimals · least count · signed errors
A caliper indicates 23.6 mm with a +0.2 mm zero error. What is the corrected reading?
Corrected = indicated − zero error = 23.6 − 0.2 = 23.4 mm.
Course connection: Practical apparatus preparation: CBSE XI, NEET/Main experimental skills and JEE Advanced General. Switch outer jaws, inner jaws or the depth rod to prepare different measurement tasks.