Key relationship
J = ∫F dt = Δp = −mu; triangular pulse: |Fpeak| = 2mu/τ.
Physics · Class 11
Momentum is mv. Newton’s second law links force to its rate of change; integrating force over time gives impulse. Both the short and long triangular force pulses remove the same incoming momentum. The broader pulse needs a lower peak but produces a longer stopping distance.
Open the interactive experiment →விசை–நேர வரைபடத்தின் பரப்பளவு உந்தம் மாற்றத்திற்குச் சமம். நிறுத்தும் நேரம் அதிகரித்தால் அதே உந்தம் மாற்றத்திற்கான உச்ச விசை குறையும்.
J = ∫F dt = Δp = −mu; triangular pulse: |Fpeak| = 2mu/τ.
Momentum is mv. Newton’s second law links force to its rate of change; integrating force over time gives impulse. Both the short and long triangular force pulses remove the same incoming momentum. The broader pulse needs a lower peak but produces a longer stopping distance.
A smaller peak force can still produce the same impulse if it acts for longer.
A prescribed triangular stopping force brings the object to rest without rebound. Force opposes incoming motion. Animation stops at the contact end.
Relate force-time area, impulse, momentum change and peak force.
Compare hard and soft presets with unchanged mass and speed. Scrub across the triangular pulse.
A catcher moves the hands backward to extend the stopping time of a ball.
A 2 kg object at 5 m/s has 10 kg·m/s momentum. A 1 s triangular stop needs a 20 N peak and impulse −10 N·s.
Impulse explains cushioning; a force value alone does not specify the change in momentum.
Vector components · velocity · SI units
If stopping time doubles with the same triangular shape and momentum change, peak force is…
The triangle area is ½Fpeakτ. A doubled base requires half the height to retain the area.
Course connection: CBSE XI Chapter 4; NEET/Main Unit 3; JEE Advanced Mechanics. Apply each exam’s stated assumptions.