Key relationship
FAB = −FBA; ΔvA = −Fτ/mA; ΔvB = Fτ/mB.
Physics · Class 11
Each skater exerts a force on the other. The two forces are equal and opposite at the same instant, but act on different bodies. They therefore cannot cancel in the force equation for one skater. The lighter skater changes velocity more; their momentum changes remain equal and opposite.
Open the interactive experiment →வினை மற்றும் எதிர்வினை விசைகள் சமமாகவும் எதிர்திசையிலும் வெவ்வேறு பொருட்களில் செயல்படும். நிறை குறைந்தவரின் வேக மாற்றம் அதிகம்.
FAB = −FBA; ΔvA = −Fτ/mA; ΔvB = Fτ/mB.
Each skater exerts a force on the other. The two forces are equal and opposite at the same instant, but act on different bodies. They therefore cannot cancel in the force equation for one skater. The lighter skater changes velocity more; their momentum changes remain equal and opposite.
Third-law forces cancel only when summing the whole two-body system, not for either body alone.
Two initially stationary point-mass skaters on frictionless ice; constant mutual push for τ; external horizontal force zero.
Identify the bodies in a third-law pair and compare force, acceleration and impulse.
Use equal masses, then light and heavy skaters. Observe equal momentum magnitudes and different velocities.
Two people pushing apart on skateboards feel the same interaction while moving differently.
A 40 N push for 1 s gives impulses −40 and +40 N·s. For 50 and 80 kg, velocities are −0.8 and +0.5 m/s.
Labeling the receiving body prevents common free-body diagram errors.
Vector components · velocity · SI units
Why do the mutual pushes not cancel for skater A?
A’s force equation includes forces acting on A. The paired reaction acts on B.
Course connection: CBSE XI Chapter 4; NEET/Main Unit 3; JEE Advanced Mechanics. Apply each exam’s stated assumptions.