Key relationship
α=ε at thermal equilibrium (same wavelength/direction); net greybody flux=ασ(Tenclosure⁴−Tsurface⁴).
Physics · Class 11
A surface that absorbs strongly also emits strongly under matching conditions. In an enclosure of the same temperature, absorbed and emitted power balance for every absorptivity. Unequal temperatures produce a net exchange.
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α=ε at thermal equilibrium (same wavelength/direction); net greybody flux=ασ(Tenclosure⁴−Tsurface⁴).
A surface that absorbs strongly also emits strongly under matching conditions. In an enclosure of the same temperature, absorbed and emitted power balance for every absorptivity. Unequal temperatures produce a net exchange.
A shiny weak absorber is also a weak emitter under the same conditions.
Opaque grey surface in a uniform black enclosure. Wavelength-independent α is an idealization of Kirchhoff law; positive net flux heats the surface.
Link absorptive and emissive powers and identify equilibrium.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
At α=0.8, enclosure 600 K and surface 500 K, net flux=0.8σ(600⁴−500⁴)≈3044 W/m² into the surface.
The model connects compare absorption and emission with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
At equal surface and enclosure temperatures, what is net radiation?
α multiplies both equal blackbody fluxes, so their difference is zero.
Course connection: Class XI Chapter 10. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.