Key relationship
Kmax=hν−φ when hν>φ; eVs=Kmax; ν₀=φ/h.
Physics · Class 12
Dual Nature of Radiation & Matter
A photon must supply the work function before an electron can escape. Its remaining energy is the maximum kinetic energy. Greater intensity increases emission rate above threshold, while greater frequency raises maximum electron energy.
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Kmax=hν−φ when hν>φ; eVs=Kmax; ν₀=φ/h.
A photon must supply the work function before an electron can escape. Its remaining energy is the maximum kinetic energy. Greater intensity increases emission rate above threshold, while greater frequency raises maximum electron energy.
High intensity cannot overcome the threshold in the one-photon model.
One-photon emission from an ideal surface; no multiphoton effects. Below threshold no emission. Relative intensity scales available electron count after emission, not Kmax.
Separate threshold, stopping potential and emission rate.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
At800 THz and φ2 eV, Kmax≈1.309 eV and Vs≈1.309 V.
The model connects photoelectric threshold with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
Above threshold, increasing intensity alone changes Kmax how?
Kmax=hν−φ depends on frequency and material.
Course connection: Class XII Chapter 11. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.