Key relationship
E=½kA²; U=½kx²; K=E−U.
Physics · Class 11
At turning points the oscillator stores all energy as spring potential energy. At equilibrium it has maximum kinetic energy. Their sum stays constant even though each part changes twice during a complete oscillation.
Open the interactive experiment →முனைகளில் நிலை ஆற்றல் அதிகம்; சமநிலை நிலையில் இயக்க ஆற்றல் அதிகம். இரண்டு ஆற்றல்களின் கூட்டுத்தொகை மாறாது.
E=½kA²; U=½kx²; K=E−U.
At turning points the oscillator stores all energy as spring potential energy. At equilibrium it has maximum kinetic energy. Their sum stays constant even though each part changes twice during a complete oscillation.
Energy returns twice per oscillation to the same partition, while signed displacement does not.
Ideal frictionless mass–spring SHM with constant total mechanical energy. Bars show energy amounts at the current phase, using a common scale.
Relate oscillator position to the exchange of kinetic and potential energy.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
With k=10 N/m and A=0.2 m, total energy=0.2 J. At x=A/2, U=0.05 J and K=0.15 J.
The model connects track energy through one oscillation with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
Where is SHM kinetic energy greatest?
At x=0 the spring potential energy is zero and K equals total energy.
Course connection: Class XI Chapter 13. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.