Key relationship
T=2π√(L/g); θ(t)=θ₀cos(√(g/L)t).
Physics · Class 11
At small angles the pendulum has a restoring acceleration proportional to angular displacement. A longer string increases period, while greater gravity decreases it. The ideal small-angle period is independent of bob mass.
Open the interactive experiment →சிறிய கோண ஊசலின் காலம் 2π√(L/g). நீளம் அதிகரித்தால் காலம் அதிகரிக்கும்; நிறை அதை மாற்றாது.
T=2π√(L/g); θ(t)=θ₀cos(√(g/L)t).
At small angles the pendulum has a restoring acceleration proportional to angular displacement. A longer string increases period, while greater gravity decreases it. The ideal small-angle period is independent of bob mass.
Large-amplitude pendulum motion does not have exactly this amplitude-independent period.
Point bob on a massless inextensible string; no air resistance, small angle ≤15°. Period formula omits finite-amplitude correction and bob mass does not enter.
Relate pendulum geometry and gravity to small-angle timing.
Try both scenarios, change one control, and predict the result before checking the graph and readouts.
Change one input while keeping the others fixed, as you would in a controlled experiment.
For L=1 m and g=9.8 m/s², T=2.007 s. At lunar gravity 1.6 m/s² the same pendulum has T=4.967 s.
The model connects tune a small-angle pendulum with an observable reading. Check the equation and assumptions before applying it.
SI units · algebra · graph reading
How does period change when length quadruples?
T is proportional to √L.
Course connection: Class XI Chapter 13. Consult the roadmap for CBSE, NEET, JEE Main and Advanced scope.